“…This shows the existence of the triangular PBIBDs (( n+2 2 ), n 2 − 1, 2n − 3, (n + 2)/2; (0, 1)) and (( n+1 2 ), n 2 − 1, 2n − 3, n/2; (0, 1)) is equivalent. Chang et al [22] (also in [56, p. 152]) give a list of 18 unsolved triangular PBIBDs, which we may update by noting that four (7,13,14,15) have now been constructed ( [6], [23, Designs T41, T54, T91]), including the T (10) Seiden case above, and its T (9) reduction, and that four (3,11,16,18) , 1), we record the construction in [14]; we construct a {47; 5, 7, 9}-arc in PG (2,8) by deleting a hyperoval and an external line, then line-flipping an 8-line; we then apply Lemma 12.17 with k = 5, v = 47, f = 5, and a = 1.…”
Section: Lemma 132 If T [K 1; M] Exists Then We May Construct Thementioning
“…In the following lemma, we summarize the current results and the reader is referred to [3,7] for more details. (h, n) ∈ {(1, 10), (3, 6), (3, 18), (3, 28), (3, 34), (6,18), (6,19), (6, 23)}.…”
Section: Constructions By Hmolsmentioning
confidence: 99%
“…n , with the possible exception of (h, n) ∈ {(1, 6), (3,6), (3,18), (3,28), (3,34), (6,18), (6,19), (6, 23)}.…”
Section: Lemma 36 If H ≥ 1 and N ≥ 5 Then There Is A 5-hpmd Of Typmentioning
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