The three-particle Bell inequality, Eq. (11) in [1], as used in our paper reads 1 + P (z i = −1,z j = −1,z k = 1) + P (z i = −1,z j = 1,z k = −1) + P (z i = 1,z j = −1,z k = −1)This interpretation of Eq. (11) in [1] is unfortunately not a true Bell inequality because, for a given mapping of the particle number {1,2,3} onto {i,j,k}, one can find a local hidden variable (LHV) model that violates the inequality. At the time of writing, we believed that while one can find LHV models that violate any specific mapping, one could not, with the same model, violate more than one of the three ensuing inequalities due to different mappings. Thus, if the choice of mapping (and hence the choice of measurement performed) was done outside the light cone (to close the communication loophole), the inequalities would discriminate between LHV and nonlocal models. We have, however, found that this is not true. Denote a LHV preparation of the three particles ), where z 1 = −1 means that if particle 1 is measured in the Z basis, the result is always −1, and if it is instead measured in the X basis, the result x 1 is 1 and so on. Assume the mapping i = 1, j = 2, and k = 3. This preparation has P (z 1 = −1,z 2 = 1,z 3 = −1) = 1, and the rest of the terms in the inequality (1) are zero. Hence, the left-hand side of (1) is 2, a clear violation of the inequality. Due to the i ↔ j symmetry of the inequality, the mapping i = 2, j = 1, and k = 3 gives the same violation of 0 0.2 0.4 0.6 0.8 1 0 0.2 0.4 0.6 0.8 1 Quantum efficiency η 2 Middle term of Bell's inequality FIG. 4. The sum of the middle terms in (2) as a function of the detector efficiency η 2 for β = 0.71 and measuring the x basis using unbalanced homodyning.the inequality. One also finds that, using this preparation but any of the four remaining mappings {1,2,3} onto {i,j,k}, the left-hand side of the inequality equals unity.Similarly, using the mappings i = 1, j = 3, and k = 2 or i = 3, j = 1, and k = 2 and the preparation ) or the mappings i = 2, j = 3, and k = 1 or i = 3, j = 2, and k = 1 and the preparation