1995
DOI: 10.1039/c39950001177
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Rhodium catalysed rearrangement of 1,2-diphenylhydrazine to o-semidine

Abstract: Rearrangement of 1,2-diphenylhydrazine occurs exclusively to o-semidine in the presence of a rhodium catalyst with o-semidine bonding to rhodium(i) as a bidentate ligand.

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Cited by 14 publications
(8 citation statements)
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“…We have previously reported the exclusive rearrangement of 1,2-N 2 H 2 Ph 2 to o-semidine (2-NH 2 C 6 H 4 NHPh) which becomes catalytic when there are two vacant sites on rhodium. 13 We now find that disproportionation of 1,2- Table 3 Selected bond lengths (Å) and angles (Њ) for complexes 1b and 1c…”
Section: Resultsmentioning
confidence: 62%
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“…We have previously reported the exclusive rearrangement of 1,2-N 2 H 2 Ph 2 to o-semidine (2-NH 2 C 6 H 4 NHPh) which becomes catalytic when there are two vacant sites on rhodium. 13 We now find that disproportionation of 1,2- Table 3 Selected bond lengths (Å) and angles (Њ) for complexes 1b and 1c…”
Section: Resultsmentioning
confidence: 62%
“…For the less heavily substituted hydrazines (Ia-Ie) there is excellent low-temperature NMR spectroscopic evidence ( 13 C and 15 N, see Tables 1 and 2 respectively) that the first formed product is 1 which is maximised at a ratio of [Rh 2 -(CO) 4 Cl 2 ] : I = 1 : 1. Thus, for complexes containing symmetrical hydrazines, (1a and Ic), there are two carbonyl resonances and, using 15 N 2 H 4 , only the lower-field resonance [δ(CO) 185.4] shows further coupling; as a result, this resonance must be due to the CO trans to the hydrazine [ 1 J( 103 Rh᎐ 13 CO) 65.8 and 2 J( 15 N᎐ 13 CO) 12.9 Hz] and the 15 N-{H} resonance of 1a and 1c is a single doublet upfield from that of the free hydrazine with At room temperature the 15 N-{ 1 H} NMR spectra are severely broadened and only one doublet is observed in the 13 CO region of the 13 C NMR spectrum of complexes 1a-1e. This suggests that the formation of 1 is reversible in solution at room temperature.…”
Section: Resultsmentioning
confidence: 99%
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“…One recent fascinating example of semidine formation is the exclusive formation of osemidine 6 when hydrazobenzene 1 is treated with a rhodium catalyst in dichloromethane solution; the o-semidine bonds to rhodium as a bidentate ligand, and presumably the geometrical requirements for this ensure that it is the preferred rearrangement product in this case 27 The reaction of 4, 4 -diiodohydrazobenzene (21) was used to investigate the acidcatalyzed disproportionation which accompanies many benzidine rearrangements 19 19 . Thus N−N bond breaking and C−C bond forming are both taking place at the transition state, and the rearrangement mechanism is probably exactly the same as for hydrazobenzene itself.…”
Section: Heavy-atom Isotope Effectsmentioning
confidence: 99%