2019
DOI: 10.1016/j.jprocont.2018.11.005
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Robust tracking of the heating value in an underground coal gasification process using dynamic integral sliding mode control and a gain-scheduled modified Utkin observer

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Cited by 19 publications
(20 citation statements)
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“…In [25], it has been assumed that all the states of the system are measurable, which is not the case practically. This discrepancy has been removed in [26], [27]. In [26], a gain scheduled modified Utkin observer (GSMUO) along with an integral SMC have been proposed to robustly track the desired trajectory of the heating value.…”
Section: A Related Workmentioning
confidence: 99%
“…In [25], it has been assumed that all the states of the system are measurable, which is not the case practically. This discrepancy has been removed in [26], [27]. In [26], a gain scheduled modified Utkin observer (GSMUO) along with an integral SMC have been proposed to robustly track the desired trajectory of the heating value.…”
Section: A Related Workmentioning
confidence: 99%
“…In this article, a special nonlinear plant will be used in which the outlets have a linear combination with the variables, the variables have a nonlinear combination with the variables, and the perturbations are entered additively. The nonlinear plant is [25], [26]:…”
Section: The Estimator For the Variables And Perturbations Estimationmentioning
confidence: 99%
“…Our estimator is applied for the variables and perturbations estimation in the gas turbine and gasification plants. The gas turbine plant is used for the electrical energy generation from the gas [25], while the gasification plant is used for the gas generation from biomass [26].…”
Section: Introductionmentioning
confidence: 99%
“…Assume, there is a fault occurring between systems (16) and (18), then TPS errors are e 1 = x 2 − q 1 x 1 , e 2 = x 3 − q 2 x 2 and e 3 = x 1 − q 3 x 3 , where q 1 q 2 q 3 = 1 and u 1 = 0 in e 3 . Therefore…”
Section: Case IV (Unknown System Parameters With a Fault)mentioning
confidence: 99%
“…NowṠ =ė 1 + 2ė 2 +ė 3 = e 2 + 2e 3 + v. By choosing v = −e 2 − 2e 3 − ks, k > 0, we haveṠ = −kS, therefore S → 0 which gives e 1 , e 2 , e 3 → 0. Case II (Known System Parameters With a Fault): Assume that there exists a fault between the systems(16) and(18), then the TPS errors x 2 −q 1 x 1 , e 2 = x 3 −q 2 x 2 and e 3 = x 1 −q 3 x 3 , where q 1 q 2 q 3 = 1. We set u 1 = 0 in e 3 so that     ė…”
mentioning
confidence: 99%