2008
DOI: 10.1039/b717506j
|View full text |Cite
|
Sign up to set email alerts
|

[Si(SiMe3)3]6Ge18M (M = Cu, Ag, Au): metalloid cluster compounds as unusual building blocks for a supramolecular chemistry

Abstract: Very recently it was shown that the metalloid cluster compound {Ge(9)[Si(SiMe(3))(3)](3)}(-) can be used for subsequent reactions as the shielding of the cluster core is rather incomplete. Here further reactions of with M(+) sources of group 11 metals are described, leading to metalloid cluster compounds of the formula {MGe(18)[Si(SiMe(3))(3)](6)}(-) (M = Ag, Cu). These reactions can be seen as first steps into a supramolecular chemistry with metalloid cluster compounds. Beside this feature, the structural pro… Show more

Help me understand this report

Search citation statements

Order By: Relevance

Paper Sections

Select...
3
1
1

Citation Types

3
75
0
4

Year Published

2011
2011
2023
2023

Publication Types

Select...
9
1

Relationship

3
7

Authors

Journals

citations
Cited by 107 publications
(82 citation statements)
references
References 36 publications
(6 reference statements)
3
75
0
4
Order By: Relevance
“…The formation of 1 can be viewed in light of the previously suggested formation of the gold analogue of 3, that is, [(Ge 9 R 3 )Au I (Ge 9 R 3 )] − (4). 46 While 3 is made by reacting Ge 9 R 3 − with the salt-like Cu(I) compound with weakly coordinating anions, Cu(Al(OR) 4 ), 47 4 is made by a reaction with a salt with ligated Au(I), (PPh 3 )AuCl, just like the reaction with (PPh 3 ) 3 CuBr for the formation of 1. It has been speculated that the formation of 4 begins with a salt-metathesis reaction to form the neutral [(Ge 9 R 3 )Au−PPh 3 ], which then exchanges the neutral PPh 3 ligand with another anionic Ge 9 R 3 − to form [(Ge 9 R 3 )Au I (Ge 9 R 3 )] − , that is: 46…”
Section: ■ Results and Discussionmentioning
confidence: 99%
“…The formation of 1 can be viewed in light of the previously suggested formation of the gold analogue of 3, that is, [(Ge 9 R 3 )Au I (Ge 9 R 3 )] − (4). 46 While 3 is made by reacting Ge 9 R 3 − with the salt-like Cu(I) compound with weakly coordinating anions, Cu(Al(OR) 4 ), 47 4 is made by a reaction with a salt with ligated Au(I), (PPh 3 )AuCl, just like the reaction with (PPh 3 ) 3 CuBr for the formation of 1. It has been speculated that the formation of 4 begins with a salt-metathesis reaction to form the neutral [(Ge 9 R 3 )Au−PPh 3 ], which then exchanges the neutral PPh 3 ligand with another anionic Ge 9 R 3 − to form [(Ge 9 R 3 )Au I (Ge 9 R 3 )] − , that is: 46…”
Section: ■ Results and Discussionmentioning
confidence: 99%
“…X compounds (X = À1: M = Cu, Ag, Au; [23,24] X = 0: M = Zn, Cd, Hg [25] ). We now present a second example of a metalloid maingroup cluster exclusively stabilized by transition-metal-based ligands, showing a unique arrangement of the tetrel atoms in the cluster core.…”
Section: àmentioning
confidence: 99%
“…The resulting bis- and tris-silylated cluster species [Ge 9 R 2 ] 2− (R = Si(TMS) 3 ) [14] and [Ge 9 R 3 ] − (R: various silyl groups) [15,16,17,18,19,20] are, due to their lower charge, soluble in common solvents (acetonitrile, thf, toluene). Subsequent reactions of the tris-silylated cluster [Ge 9 R 3 ] − (R: Si(TMS) 3 ) with coinage metal complexes, in most cases coinage metal phosphine complexes, commonly yield coinage metal-bridged cluster dimers, under the loss of the original ligand sphere of the transition metal [19,21,22]. However, there are also a few reports in which the Cu-phosphine bond is retained [18,23].…”
Section: Introductionmentioning
confidence: 99%