2020
DOI: 10.1016/j.camwa.2019.07.015
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Simulation of particles dissolution in the shear flow: A combined concentration lattice Boltzmann and smoothed profile approach

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Cited by 8 publications
(5 citation statements)
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“…In the present study, it is assumed that particles keep circular shape during the dissolution process, which is always adopted in the simulation of moving particle dissolution 26–29 . According to Fick's first law, the change rate of the i th particle mass during dissolution is calculated by integrating the mass flux of all boundary nodes associated to the particle as follows 26,28 : ddt[]ρsiπri2goodbreak=goodbreak−SiitalicJdS$$ \frac{d}{dt}\left[{\rho}_s^i\pi {\left({r}^i\right)}^2\right]=-{\int}_{S^i} JdS $$ where ri$$ {r}^i $$ and ρsi$$ {\rho}_s^i $$ are the radius and density of solid particle i , respectively; Si$$ {S}^i $$ is the surface of solid particle i .…”
Section: Methodologiesmentioning
confidence: 99%
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“…In the present study, it is assumed that particles keep circular shape during the dissolution process, which is always adopted in the simulation of moving particle dissolution 26–29 . According to Fick's first law, the change rate of the i th particle mass during dissolution is calculated by integrating the mass flux of all boundary nodes associated to the particle as follows 26,28 : ddt[]ρsiπri2goodbreak=goodbreak−SiitalicJdS$$ \frac{d}{dt}\left[{\rho}_s^i\pi {\left({r}^i\right)}^2\right]=-{\int}_{S^i} JdS $$ where ri$$ {r}^i $$ and ρsi$$ {\rho}_s^i $$ are the radius and density of solid particle i , respectively; Si$$ {S}^i $$ is the surface of solid particle i .…”
Section: Methodologiesmentioning
confidence: 99%
“…Substituting Equation (29) into Equation (30), the change of the particle radius can be obtained as follows: italicdridtgoodbreak=D2πρsiriSiCnitalicdS$$ \frac{dr^i}{dt}=\frac{D}{2{\pi \rho}_s^i{r}^i}{\int}_{S^i}\frac{\partial C}{\partial n} dS $$ Furthermore, the new radius of the solid particle i is calculated as follows 28 : rt+normalΔtigoodbreak=rti2+DnormalΔtπρsiSiCnitalicdS$$ {r}_{t+\Delta t}^i=\sqrt{{\left({r}_t^i\right)}^2+\frac{D\Delta t}{{\pi \rho}_s^i}{\int}_{S^i}\frac{\partial C}{\partial n} dS} $$ where rt+normalΔti$$ {r}_{t+\Delta t}^i $$ and rti$$ {r}_t^i $$ are the radius of the solid particle i at times t + ∆ t and t , respectively.…”
Section: Methodologiesmentioning
confidence: 99%
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