1997
DOI: 10.1103/physrevlett.78.717
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Single Hole Dynamics in theCuO2Plane at Half Filling

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Cited by 88 publications
(102 citation statements)
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“…Pothuizen et al 19 recently published results suggesting the existence of a k ជ -dependent broadening, similar in spirit to the ideas contained in this paper.…”
Section: Fig 6 Same Assupporting
confidence: 58%
“…Pothuizen et al 19 recently published results suggesting the existence of a k ជ -dependent broadening, similar in spirit to the ideas contained in this paper.…”
Section: Fig 6 Same Assupporting
confidence: 58%
“…These higher lying states in the CuO 2 plane oxychloride Sr 2 CuO 2 Cl 2 have recently been the subject of an ARPES study. 16 In this case, the next two features lying at higher BE than the ZRS were attributed to states which, at particular locations in k space ͓⌫, ( ,0͒, and ( , )͔, possess practically pure O 2p character. For Sr 2 CuO 2 Cl 2 the first of these, located at 2.85 eV, has in-plane character, whereas the second feature at ϳ4 eV should have out-of-plane character at ⌫.…”
Section: A Experimental Resultsmentioning
confidence: 99%
“…For Sr 2 CuO 2 Cl 2 the first of these, located at 2.85 eV, has in-plane character, whereas the second feature at ϳ4 eV should have out-of-plane character at ⌫. 16 These nonmixing O states are essentially uncorrelated in nature and were suggested to be the origin of the so-called ''1 eV peak'' in the high-T c cuprates, which had been discussed either in terms of an intrinsic feature of the electronic structure, 18 or in terms of a surface state. 19 On inspection of the data in Fig.…”
Section: A Experimental Resultsmentioning
confidence: 99%
See 1 more Smart Citation
“…11,12,14 The hopping matrix elements can be expressed in terms of the Slater-Koster parameters, 18 t 0 = − √ 3(pdσ)/2, t 1 = −(pdσ)/2, and t 2 = (pdπ), for the Cu-O ones, and t 3 = (1/2)((ppσ) + (ppπ)), t 4 = (1/2)((ppσ) − (ppπ)), and t 5 = (ppπ) for the O-O matrix elements. We have used the values (pdσ) = 1.5eV 9,10 and (ppπ) = −0.6eV 19 , and used the relations (ppπ) = − 1 4 (ppσ) and (pdπ) = − 1 2 (pdσ) 20 . 16.…”
Section: )mentioning
confidence: 99%