“…Given: A partial order ρ ⊆ C × C over a set C, a cost function c : C × C → N, and some k ∈ N. Output: Is there a linear order τ ⊇ ρ with c(τ \ ρ) = (x,y)∈τ \ρ c(x, y) ≤ k? Intuitively, given a partial order ρ and a cost function c, the goal is to find a linear extension of ρ incurring a cost of at most k. The only difference between CO and the original PCO problem introduced in [Dujmovic et al, 2003;Fernau, 2005] is that, in the latter, for every pair (x, y) ∈ C × C such that x and y are incomparable in ρ, the cost of (x, y) is strictly positive (c(x, y) > 0) whereas in CO, the cost can be zero (c(x, y) = 0).…”