“…Taking into account that according to (22), d(t, x) = 0 for = 1, it is preferable to choose 0 < min < 1 and max > 1 to satisfy inequality (14). On the other hand, to fulfill inequality (15), it is necessary to solve inequalities (11)-(14) with a sufficiently large value of max min . Thus, to select the parameters, the following strategy can be used along with Algorithm 1: starting with max = min = 1, it is necessary to solve the system of inequalities (11)-(13), (24), and (25) using Algorithm 1 with slightly increasing the parameter max and/or decreasing min until the inequality c 2 max ≤ c 1 min is satisfied.…”