2005
DOI: 10.1016/j.tcs.2004.04.011
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State complexity of some operations on binary regular languages

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Cited by 111 publications
(83 citation statements)
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“…As in Section 3.1.1, we need to consider three different cases, according to the state and transition complexities of the operands. Although the tight bound for (complete) state complexity can be reached over a binary alphabet [14], all automaton families used in this section have an alphabet Σ = {a, b, c}. − 5 transitions.…”
Section: Worst-case Witnessesmentioning
confidence: 99%
“…As in Section 3.1.1, we need to consider three different cases, according to the state and transition complexities of the operands. Although the tight bound for (complete) state complexity can be reached over a binary alphabet [14], all automaton families used in this section have an alphabet Σ = {a, b, c}. − 5 transitions.…”
Section: Worst-case Witnessesmentioning
confidence: 99%
“…2. As shown in [15,Theorem 5], there exists a fooling set We summarize the results given in Lemma 2 and Lemma 3 in the following theorem which provides the tight bound on the nondeterministic state complexity of complementation on prefix-free languages. This solves an open problem from [10].…”
Section: Proposition 1 ([9]) Let N ≥ 2 Andmentioning
confidence: 90%
“…. , n − 1}} be the fooling set for the language K c described in [15,Theorem 5]; notice that x S is a string, by which the initial state 1 of the NFA in Fig. 1 goes to the set S. Let us show that the set …”
Section: Theorem 3 (Complement On Non-returning Languages |σ| ≥ 2) mentioning
confidence: 99%
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