The ketene tBu2C=C=O is prepared from tBu2C=O in three steps (performable as a two‐stage operation) through elimination of HCl from the intermediate product tBu2CCl–CH=O. The acid tBu2CH–CO2H, obtainable in two, three, or four preparative stages from tBu2C=O, adds slowly to the ketene to produce the anhydride (tBu2CH–CO)2O. Elemental lithium together with ClSiMe3 converts tBu2CCl–CH=O into tBu2C=CH–OSiMe3, which is a durable precursor of tBu2CH–CH=O, making this aldehyde easily and cheaply available from tBu2C=O. By exclusion of alternative mechanistic possibilities, the reduction of tBu2CCl–CH=O by tBuMgCl is shown to involve at least one single‐electron transfer, leading to the enolate tBu2C=CH–OMgCl, which can be converted into tBu2CH–CH=O (three steps from tBu2C=O) or into tBu2C=CH–OSiMe3. Hydride transfer from NaBH4 to tBu2CCl–CH=O affords tBu2CCl–CH2OH, the transformations of which provide an entertaining set of SN1‐type reactions. Several other examples of carbenium‐type behavior are encountered in this gem‐tBu2 system; they are attributed to steric congestion, which also impedes bond rotations in the anhydride and in two esters. A convenient route to tBu2CH–C≡N (five steps from tBu2C=O) uses the conversion of tBu2C=CH–OSiMe3 into tBu2CH–CH=NOH. The slow thermal (Z)/(E) equilibration of tBu2CH–NH–CH=O reveals the ranking of ecliptic repulsions as H3C < tBu < tBu2CH.