2010
DOI: 10.1090/s0002-9947-10-04993-7
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Structure of Zariski-closed algebras

Abstract: Abstract. The objective of this paper is to describe the structure of Zariskiclosed algebras, which provide a useful generalization to finite dimensional algebras in the study of representable algebras over finite fields. Our results include a version of Wedderburn's principal theorem as well as a more explicit description using representations, in terms of "gluing" in Wedderburn components. Finally, we construct "generic" Zariski-closed algebras, whose description is considerably more complicated than the des… Show more

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Cited by 15 publications
(20 citation statements)
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“…By the Braun-Kemer-Razmyslov theorem, J ℓ 0 = 0 for some ℓ. Hence x 1 · · · x ℓ is an identity of J 0 , and thus of its Zariski closure, which is J by [9,Proposition 3.21]. In other words, J ℓ = 0.…”
Section: Review Of Zariski Closed Algebrasmentioning
confidence: 96%
See 2 more Smart Citations
“…By the Braun-Kemer-Razmyslov theorem, J ℓ 0 = 0 for some ℓ. Hence x 1 · · · x ℓ is an identity of J 0 , and thus of its Zariski closure, which is J by [9,Proposition 3.21]. In other words, J ℓ = 0.…”
Section: Review Of Zariski Closed Algebrasmentioning
confidence: 96%
“…In this section we review Zariski closed algebras, studied in [9], which form the foundation for the study of representable PI-rings. Suppose F ⊆ K is an algebraically closed field.…”
Section: Review Of Zariski Closed Algebrasmentioning
confidence: 99%
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“…It implies Sμ(A) = Sμ(Γ), that contradicts to the properties of A. Thereforeg j | (17) = 0. Thus in any case hμ| (17)…”
Section: Lemma 43 Letmentioning
confidence: 99%
“…If a graded pure form polynomials j in (16) depends essentially on Z then γ−1+μ m=1 ϑ∈ G A Z ϑ m s jgj | (17) = 0, since the forms are zero on radical elements (see (12)). Ifs j does not depend on Z then (17) = 0 in A i then one of the multihomogeneous on degrees components ofg j is aμ-boundary polynomial for A i . And it is not aμ-boundary polynomial for Γ, because it belongs to Γ.…”
Section: Lemma 43 Letmentioning
confidence: 99%