“…Following Lemmas 5.8 and 5.9, we see that there is an element t ∈ B such thatg(b, t) = a = 1. Since g ≤ n, we have by [5,Theorem 3.4] that | supp(g)| ≤ n. As B is residually-C and b t is C-separable, we have by Lemma 5.10 that there is a subgroup N B ∈ N C (B) such that π NB is injective on supp(g), π NB ( b t 1 ) = π NB ( b t 2 ) for t 1 , t 2 ∈ supp(g), and |B/N B | ≤ (Cyclic B,C (n)) n 2 . Letting π : A ≀ B → A ≀ (B/N B ) be the natural extension given by Lemma 4.3, we have that π(f )(b, t) = a. Lemma 5.9 implies that…”