“…For input (α, β) = (1, 1) the output of AND is 1, thus the kernel of H 0 (1, 1) should be one-dimensional and contain a vector of the form z = (p 1 , p 2 , p 3 , 1) so that it has a non-zero component (which we fix equal to 1) on the reading block. From (16), the condition that z belongs to the kernel of H 0 (1, 1) is equivalent to C 11 p + u = 0 and u T p + B = 0 (in this case B is just a number), with p = (p 1 , p 2 , p 3 ). The first condition gives p = −C −1 11 u.…”