The aluminum amides R 2 AlN(Ar)SiMe 3 [R = Et, Ar = Dipp, 1 (Dipp = 2,6-iPr 2 C 6 H 3 -); R = iBu, Ar = Dipp, 2; R = Et, Ar = Mes, 3 (Mes = 2,4,6-Me 3 C 6 H 2 -); R = iBu, Ar = Mes, 4] were prepared by ethane or hydrogen elimination reaction between Et 3 Al or iBu 2 AlH and ArN(H)SiMe 3 in refluxing hexane solution. The LiCl salt elimination route resulted in the formation of the monomeric aluminum amide Et 2 AlN(Mes)-SiPh 3 (5) featuring three-coordinate aluminum and nitrogen