2015
DOI: 10.1016/j.disc.2015.04.019
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The complexity of the 3-colorability problem in the absence of a pair of small forbidden induced subgraphs

Abstract: a b s t r a c tWe completely determine the complexity status of the 3-colorability problem for hereditary graph classes defined by two forbidden induced subgraphs with at most five vertices.

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Cited by 12 publications
(3 citation statements)
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“…. 5.Malyshev proved that 3‐ Coloring is sans-serifNP‐complete for (C3++,C4+P1¯,K1,4)‐free graphs after previously proving that 3‐ Coloring is sans-serifNP‐complete for (C3++,K1,4)‐free graphs . Note that Theorem (i):3 already implies that 3‐ Coloring is sans-serifNP‐complete for (C4+P1¯,K1,4)‐free graphs. …”
Section: Results and Open Problems For (H1h2)‐free Graphsmentioning
confidence: 96%
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“…. 5.Malyshev proved that 3‐ Coloring is sans-serifNP‐complete for (C3++,C4+P1¯,K1,4)‐free graphs after previously proving that 3‐ Coloring is sans-serifNP‐complete for (C3++,K1,4)‐free graphs . Note that Theorem (i):3 already implies that 3‐ Coloring is sans-serifNP‐complete for (C4+P1¯,K1,4)‐free graphs. …”
Section: Results and Open Problems For (H1h2)‐free Graphsmentioning
confidence: 96%
“…Malyshev characterized exactly those pairs of graphs H 1 and H 2 each with at most five vertices for which 3‐ Coloring is polynomial‐time solvable when restricted to (H1,H2)‐free graphs. His main result, obtained by combining known results with new results, can be summarized as follows.…”
Section: Results and Open Problems For (H1h2)‐free Graphsmentioning
confidence: 99%
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