2008
DOI: 10.1090/s0002-9939-08-09333-7
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The effective Chebotarev density theorem and modular forms modulo $\mathfrak m$

Abstract: Abstract. Suppose that f (resp. g) is a modular form of integral (resp. halfintegral) weight with coefficients in the ring of integers O K of a number field K. For any ideal m ⊂ O K , we bound the first prime p for which f | T p (resp. g | T p 2 ) is zero (mod m). Applications include the solution to a question of Ono (2001) concerning partitions.

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Cited by 4 publications
(7 citation statements)
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“…It is however not clear how one can ensure that ν ℓ (• • • ) = 0 without using 'analytic' inputs as in our paper, it does not help that we do not have much control on the set {n j } from [17]. If analytic inputs are used, then the ensuing bound on ℓ would be similar to ours.…”
Section: 11mentioning
confidence: 76%
“…It is however not clear how one can ensure that ν ℓ (• • • ) = 0 without using 'analytic' inputs as in our paper, it does not help that we do not have much control on the set {n j } from [17]. If analytic inputs are used, then the ensuing bound on ℓ would be similar to ours.…”
Section: 11mentioning
confidence: 76%
“…One can use these versions to redefine the sets S j,l , S j and S, see Remark 2.2. The following can be found as Theorem 2.2 and Proposition 2.3 in [5].…”
Section: Linear Dependence Of Rational Pointsmentioning
confidence: 97%
“…The cusp form g(z) is determined by a result of Treener [17]. Moreover, work of Lichtenstein [14] allows us to bound the first prime p such that T (p 2 ) annihilates g(z). The details of the construction of g(z) follow.…”
Section: Harmonic Maass Formsmentioning
confidence: 99%
“…We end this section by recalling the action of Hecke operators T (p 2 ) on half integral weight cusp forms and stating a result of Lichtenstein [14], which will allows us to bound the smallest prime p such that g(z) | T (p 2 ) ≡ 0 (mod ℓ j ). If χ is a quadratic character, g(z) = a(n)q n ∈ M λ+1/2 (4N, χ), and (p, 4N) = 1 then g(z) | T (p 2 ) := a(p 2 n) + (−1) λ n p χ(p) p λ−1 a(n) + p 2λ−1 a(n/p 2 ) q n .…”
Section: 2mentioning
confidence: 99%
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