1995
DOI: 10.1007/bf01496584
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The equivalence theorem and effective Lagrangians

Abstract: We point out that the equivalence theorem, which relates the amplitude for a process with external longitudinally polarized vector bosons to the amplitude in which the longitudinal vector bosons are replaced by the corresponding pseudo-Goldstone bosons, is not valid for effective Lagrangians. However, a more general formulation of this theorem also holds for effective interactions. The generalized theorem can be utilized to determine the high-energy behaviour of scattering processes just by power counting and … Show more

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Cited by 21 publications
(24 citation statements)
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“…3. We use the Equivalence Theorem (ET) [49][50][51][52] that has been proven to work also within the context of a SIEWSBS [53][54][55][56]. For the present computation it means that, for energies well above the EW gauge boson masses, m W , m Z ≪ √ s, the following approximations can be done:…”
Section: Jhep07(2014)149mentioning
confidence: 99%
“…3. We use the Equivalence Theorem (ET) [49][50][51][52] that has been proven to work also within the context of a SIEWSBS [53][54][55][56]. For the present computation it means that, for energies well above the EW gauge boson masses, m W , m Z ≪ √ s, the following approximations can be done:…”
Section: Jhep07(2014)149mentioning
confidence: 99%
“…These unitarity violations are associated with the longitudinal modes of the W bosons as can be seen by inspection of our results or, more generally, by a straightforward application of the equivalence theorem [51,52]. A general discussion of the equivalence theorem in the context of chiral Lagrangians can be found in [53,54]. In this section we will rederive the large-s limit of the e + e − → W + W − cross-section in a more transparent way by working in the Landau gauge, where the Goldstone modes ϕ ± appear explicitly.…”
Section: High-energy Limit and The Goldstone Boson Equivalence Theoremmentioning
confidence: 55%
“…This is true for all terms in (3.16) 6 . For the scattering of two vector-bosons into two vector-bosons the O(s 0 ) behavior for all terms has been shown in [26]. Using the formalism of [26], one easily generalizes this result of a constant, O(s 0 ), behavior to all two-boson into two-boson processes, i.e.…”
Section: Non-standard Couplings Among Vector Bosonsmentioning
confidence: 80%
“…For the scattering of two vector-bosons into two vector-bosons the O(s 0 ) behavior for all terms has been shown in [26]. Using the formalism of [26], one easily generalizes this result of a constant, O(s 0 ), behavior to all two-boson into two-boson processes, i.e. for any combination of external Higgs bosons and vector-bosons in an arbitrary polarization state.…”
Section: Non-standard Couplings Among Vector Bosonsmentioning
confidence: 81%
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