2015
DOI: 10.1016/j.jctb.2015.01.001
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The Erdős–Hajnal conjecture for paths and antipaths

Abstract: International audienceWe prove that for every k, there exists c k > 0 such that every graph G on n vertices with no induced path P k or its complement P k contains a clique or a stable set of size n c k. An n-graph is a graph on n vertices. For every vertex x, N (x) denotes the neighborhood of x, that is the set of vertices y such that xy is an edge. The degree deg(x) is the size of N (x). In this note, we only consider classes of graphs that are closed under induced subgraphs. Moreover a class C is strict if … Show more

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Cited by 31 publications
(46 citation statements)
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“…Proof of Theorem 4, part (1). Let V be an n-element set and let V 1 , V 2 , V 3 , V 4 be a partition of V into four sets of size roughly n/4.…”
Section: Sharp Threshold For Intersection Graphs-proof Of Theoremmentioning
confidence: 99%
“…Proof of Theorem 4, part (1). Let V be an n-element set and let V 1 , V 2 , V 3 , V 4 be a partition of V into four sets of size roughly n/4.…”
Section: Sharp Threshold For Intersection Graphs-proof Of Theoremmentioning
confidence: 99%
“…Recently, a new approach for tackling this conjecture has been introduced: forbidding both a graph and its complement. This approach provides a large amount of results for paths (see [4,9,7,8], for instance). In particular, Bousquet, Lagoutte, and Thomassé proved that for every k, the class of graphs with no P k nor its complement satisfies the Erdős-Hajnal property [4].…”
mentioning
confidence: 99%
“…This approach provides a large amount of results for paths (see [4,9,7,8], for instance). In particular, Bousquet, Lagoutte, and Thomassé proved that for every k, the class of graphs with no P k nor its complement satisfies the Erdős-Hajnal property [4]. A recent survey of Chudnovsky [6] overviews most of the results known about this conjecture and its equivalent directed version.…”
mentioning
confidence: 99%
“…Finally, the family of central nebulae contains infinitely many tournaments with prime subtournaments that are neither galaxies nor constellations. For example, take a tournament of twelve vertices {1, … , 12} and with the set of backward edges under ordering (1, … , 12) of the form: {(4, 1), (8,4), (5,3), (9,5), (6,2), (11,6), (10,7), (12,10)}. Using that ordering one can note that is a central nebula.…”
Section: If Is Either a Left Or A Right Nebula Then { mentioning
confidence: 99%
“…These results were further refined in . Surprisingly, a much more general result holds: excluding an arbitrary path and its complement implies the existence of a polynomial‐size clique or stable set (). Several interesting results regarding excluding pairs of graphs are included in .…”
Section: Introductionmentioning
confidence: 99%