2015
DOI: 10.1007/s00440-015-0636-6
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The random k cycle walk on the symmetric group

Abstract: Abstract. We study the random walk on the symmetric group S n generated by the conjugacy class of cycles of length k. We show that the convergence to uniform measure of this walk has a cut-off in total variation distance after n k log n steps, uniformly in k = o(n) as n → ∞. The analysis follows from a new asymptotic estimation of the characters of the symmetric group evaluated at cycles.

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Cited by 11 publications
(34 citation statements)
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“…Thus, in principle, the techniques developed here could be used to study a random walk generated by elements of SO(k) ⊂ SO(2n + 1) instead of by rotations in a single plane. A similar formula for character ratios on the symmetric group appears in [11].…”
Section: Introductionmentioning
confidence: 70%
“…Thus, in principle, the techniques developed here could be used to study a random walk generated by elements of SO(k) ⊂ SO(2n + 1) instead of by rotations in a single plane. A similar formula for character ratios on the symmetric group appears in [11].…”
Section: Introductionmentioning
confidence: 70%
“…We establish the limit profile for 2 ≤ k n. There are parity constraints. To handle such parity constraints, we follow the set-up used by Hough [14]:…”
Section: Definition Bmentioning
confidence: 99%
“…The case of random transpositions, ie k = 2, was one of the first Markov chains studied using representation theory; cutoff was established by Diaconis and Shahshahani [10]. For general 2 ≤ k n, cutoff was established for by Hough [14] using representation theory. Berestycki, Schramm and Zeitouni [3] previously established the same result for k independent of n, using probabilistic arguments instead of representation theory.…”
Section: Theorem B (Random K-cyclesmentioning
confidence: 99%
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“…Moreover, by the same argument as for The cut-off parameter is the same as in the classical case (see [7]). We can even consider the conjugacy class of m-cycles for any integer m and, for N large enough, the cut-off will appear at N ln(N)/m steps, again as in the classical case [8].…”
Section: 1mentioning
confidence: 99%