“…For all u and arbitrary e n such that u P B M4 1 and M 4 ( Ire n us, we have that M 4 ( Gruabs, and given that there is such a u, we have that aZ 1 b. But one of the formulas in Θ implies that there is also v P B M4 For clause (2) in Definition 4, suppose that i P t1, 2u and xZ i y, so there is e n (n P ω) in the sequence p˚q such that there is u P B M4 i , M 4 ( Ire n us and M 4 ( Gruxys. Now let R rU M 4 j s M 4 |K ybc for some b, c P U M4 j , i.e., R 4 ybc by Lemma 10.…”