1999
DOI: 10.1006/jnth.1998.2365
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The Size of (q; q)nforqon the Unit Circle

Abstract: There is increasing interest in q-series with |q| =1. In analysis of these, all important role is played by the behaviour as n Ä ofWe show, for example, that for almost all q on the unit circle log |(q; q) n |=O(log n) 1+=iff =>0. Moreover, if q=exp(2?i{) where the continued fraction of { has bounded partial quotients, then the above relation is valid with ==0. This provides an interesting contrast to the well known geometric growth as n Ä of1999 Academic Press

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Cited by 36 publications
(60 citation statements)
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“…for any ε > 0, and this holds for almost every α [8]. In the opposite direction, P n (α) grows almost linearly for infinitely many n. We have that lim sup n→∞ log P n (α) log n ≥ 1 for all irrationals α ∈ (0, 1).…”
Section: Growth Of P N (α)mentioning
confidence: 89%
See 2 more Smart Citations
“…for any ε > 0, and this holds for almost every α [8]. In the opposite direction, P n (α) grows almost linearly for infinitely many n. We have that lim sup n→∞ log P n (α) log n ≥ 1 for all irrationals α ∈ (0, 1).…”
Section: Growth Of P N (α)mentioning
confidence: 89%
“…In his 1999 paper [8], Lubinsky illustrates a significant difference in nature of P n (α) depending on whether or not the continued fraction expansion of α has bounded coefficients. If this is the case, then there exist positive constants C 1 and C 2 such that…”
Section: Significance Of the Continued Fraction Expansionmentioning
confidence: 99%
See 1 more Smart Citation
“…As a consequence of Theorem 1.1, Mestel and Verschueren show in [15] that one can establish polynomial bounds on P n (α) when α = ω is the golden mean. Specifically, they show that in this case there exist constants K 1 ≤ 0 < 1 ≤ K 2 such that n K 1 ≤ P n (α) ≤ n K 2 , (8.1) for all n ∈ N. It is worth mentioning that this is not a new result; in a paper from 1999, Lubinsky studies the product P n (α) in the language of q-series [10]. In particular, he proves that (8.1) holds whenever α = [0; a 1 , a 2 , .…”
Section: Discussionmentioning
confidence: 96%
“…Acknowledgment. We thank Dmitriy Bilyk who drew our attention to the results given in [23,30], and [41].…”
mentioning
confidence: 99%