2013
DOI: 10.1090/s0002-9947-2013-05812-6
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The truncated matrix-valued $K$-moment problem on $\mathbb {R}^d$, $\mathbb {C}^d$, and $\mathbb {T}^d$

Abstract: The truncated matrix-valued K-moment problem on R d , C d , and T d will be considered. The truncated matrix-valued K-moment problem on R d requires necessary and sufficient conditions for a multisequence of Hermitian matrices {S γ } γ∈Γ (where Γ is a finite subset of N d 0) to be the corresponding moments of a positive Hermitian matrix-valued Borel measure σ, and also the support of σ must be contained in some given non-empty set K ⊆ R d , i.e., (0.1) S γ = R d ξ γ dσ(ξ), for all γ ∈ Γ, and (0.2) supp σ ⊆ K. … Show more

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Cited by 26 publications
(18 citation statements)
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“…If Φ(n) 0 and there exist Θ z (n) and Θz(n) such that Proof. This is a particular case of Theorem 3.4 in [15] for K = C and Λ = {(j, k) ∈ N 2 0 : 0 ≤ j + k ≤ n}. Here N 2 0 denotes the set of all 2-tuples of nonnegative integers.…”
Section: Theorem 25 [4]mentioning
confidence: 92%
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“…If Φ(n) 0 and there exist Θ z (n) and Θz(n) such that Proof. This is a particular case of Theorem 3.4 in [15] for K = C and Λ = {(j, k) ∈ N 2 0 : 0 ≤ j + k ≤ n}. Here N 2 0 denotes the set of all 2-tuples of nonnegative integers.…”
Section: Theorem 25 [4]mentioning
confidence: 92%
“…Theorem 2.6. [15] Let s = {s jk } 0≤j+k≤2n+1 be given. If Φ(n) 0 and there exist Θ z (n) and Θz(n) such that Proof.…”
Section: Theorem 25 [4]mentioning
confidence: 99%
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“…When m = 2n + 1, partial solutions can be seen in [14] and [16] as well as a solution to the truncated matrix moment problem; in particular, a solution to the cubic complex moment problem (when n = 1) was given in [15]. However, the problem is still often for n ≥ 2.…”
Section: Introductionmentioning
confidence: 99%