2009
DOI: 10.1134/s1063778809100135
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Three-body structure of A = 9 isobars (Be, Li, and C) and elastic proton scattering

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Cited by 10 publications
(12 citation statements)
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“…The structure of 9 Be has been extensively studied, both theoretically [1][2][3][4][5][6][7][8][9][10][11][12][13][14][15][16] and experimentally [17][18][19][20][21][22][23][24][25][26][27], but there are still large uncertainties in the structure and decay of the low-lying excited states. This is surprising and worrisome in view of the great effort and the expected rather accurate approximation as a simple three-body system where the intrinsic degrees of freedom are inactive.…”
Section: Introductionmentioning
confidence: 99%
“…The structure of 9 Be has been extensively studied, both theoretically [1][2][3][4][5][6][7][8][9][10][11][12][13][14][15][16] and experimentally [17][18][19][20][21][22][23][24][25][26][27], but there are still large uncertainties in the structure and decay of the low-lying excited states. This is surprising and worrisome in view of the great effort and the expected rather accurate approximation as a simple three-body system where the intrinsic degrees of freedom are inactive.…”
Section: Introductionmentioning
confidence: 99%
“…The 9 Ве nucleus is a strongly deformed stable nucleus whose quadrupole moment is Q = 52.88(38) mb [1]. It is loosely bound in the channels 9 Ве → 8 Ве + n [1] and 9 Ве → α + α + n [1] (the respective binding energies are ε = 1.67 MeV and ε = 1.57 MeV), this being a direct indication of its three-particle α + α + n structure.…”
Section: Introductionmentioning
confidence: 99%
“…It is loosely bound in the channels 9 Ве → 8 Ве + n [1] and 9 Ве → α + α + n [1] (the respective binding energies are ε = 1.67 MeV and ε = 1.57 MeV), this being a direct indication of its three-particle α + α + n structure. The wave functions calculated on the basis of the α + α + n model [2][3][4][5], which take this circumstance into account, describe well the static properties of the 9 Ве nucleus; electromagnetic form factors; and observables of elastic π 9 Ве, K 9 Ве, and p 9 Ве scattering [2][3][4][5][6][7][8][9]. The 9 Ве nucleus is a Borromean nucleus, since, within the α + α + n three-particle picture, there are no two components that could form a bound system (the same is true for 6 He in the α + n + n channel and for 11 Li in the 9 Li + n + n channel).…”
Section: Introductionmentioning
confidence: 99%
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