2017
DOI: 10.1016/j.topol.2017.08.018
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Transversal, T1-independent, and T1-complementary topologies

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Cited by 10 publications
(9 citation statements)
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“…Since every infinite subgroup H of G is C ′ -cofinite and is not abelian by Proposition 5.4(2), we deduce by the above argument that H is not solvable. By Proposition 5.4 (5), an infinite non-abelian C ′ -cofinite group is torsion. Now we prove that G is bounded, of prime exponent bigger than 3.…”
Section: ′ -Cofinite Groupsmentioning
confidence: 98%
See 2 more Smart Citations
“…Since every infinite subgroup H of G is C ′ -cofinite and is not abelian by Proposition 5.4(2), we deduce by the above argument that H is not solvable. By Proposition 5.4 (5), an infinite non-abelian C ′ -cofinite group is torsion. Now we prove that G is bounded, of prime exponent bigger than 3.…”
Section: ′ -Cofinite Groupsmentioning
confidence: 98%
“…(3) is immediate and (4) follows from (3). (5). The group G cannot contain infinite cyclic subgroups H. Indeed, such an H is C ′ -cofinite, by (3).…”
Section: ′ -Cofinite Groupsmentioning
confidence: 99%
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“…Our first observation is that the group G 1 is not precompact -otherwise continuous characters of G 1 would separate elements of G 1 . Since every non-zero element of the countable group G 1 has order 2, one can apply [5,Theorem 5.28] to find an open neighborhood U of zero e 1 in G 1 and a (necessarily discontinuous) automorphism f of the group G 1 such that f (U) ∩ U = {e 1 }. In other words, the group G 1 is self-transversal.…”
Section: Proofmentioning
confidence: 99%
“…Our first observation is that the group G 1 is not precompact -otherwise continuous characters of G 1 would separate elements of G 1 . Since every non-zero element of the countable group G 1 has order 2, one can apply ( [16], Theorem 5.28) to find an open neighborhood U of zero e 1 in G 1 and a (necessarily discontinuous) automorphism f of the group G 1 such that f (U) ∩ U = {e 1 }. In other words, the group G 1 is self-transversal.…”
Section: Proofmentioning
confidence: 99%