1967
DOI: 10.1103/physrev.159.664
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Trapping Processes in Amorphous Selenium

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1969
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Cited by 27 publications
(8 citation statements)
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“…While the drift mobility decreases exponentially with decreasing temperature, the lifetime increases exponentially. This may seem unusual, but it is exactly what would be expected in the case of shallow trap controlled transport and a set of deep traps [19]. Notice that the activation energies for the lifetime are not too different than those corresponding activation energies for the drift mobility.…”
Section: Resultsmentioning
confidence: 78%
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“…While the drift mobility decreases exponentially with decreasing temperature, the lifetime increases exponentially. This may seem unusual, but it is exactly what would be expected in the case of shallow trap controlled transport and a set of deep traps [19]. Notice that the activation energies for the lifetime are not too different than those corresponding activation energies for the drift mobility.…”
Section: Resultsmentioning
confidence: 78%
“…The thermally activated behavior in the drift mobility and the lifetime arise from the temperature dependence of , or r , inasmuch as carrier release is thermally activated; probability of release per unit time is o Ϫ1 exp(−E t /kT) where o is a phonon (an attempt to escape) frequency and E t is the energy depth of the traps from the transport band edge. The measured drift mobility from TOF and the lifetime from IFTOF are given by [19] = o and = o / so that…”
Section: Resultsmentioning
confidence: 99%
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“…This gives Because exp(-r/T1), exp(-t/T2), and exp(-emt) are linearly independent, we have c=o (14) where r = l / r l or 1/r2. Rearranging eq 15 we have r 2 -( 1 / r + N t C , + e , , ) r + ( e , / r ) = O (16) The solutions of eq 16 are…”
Section: (3)mentioning
confidence: 98%
“…The latter two factors are denoted by em, so that the generation rate is given by = Vt where r = 1/tj or l/r2. Rearranging eq 15 we have r2-(\/r + NtCllt + ejr + (em/r) = 0 (16) The solutions of eq 16 are r±=l/2[(l/T + NtCnt + em)± ((l/T + ^Cm + em)2-4em/r)'/2] (17) Choosing two linearly independent solutions we have r, = l/r+and r2 = l/r_ (18) and…”
Section: The Photoconductivity Modelmentioning
confidence: 99%