2006
DOI: 10.1090/conm/420/07967
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Two statements about infinite products that are not quite true

Abstract: infinite product module, inverse limit module, dichotomy of finite or uncountable generation, homomorphism to infinite direct sum, left perfect ring; infinite symmetric group, finite generation of power or ultrapower of an algebra over the diagonal subalgebra.URLs of this preprint: http://math.berkeley.edu/∼ gbergman/papers/P vs cP.{tex,dvi,ps, pdf} (i.e., four versions, .../.tex, .../.dvi, .../.ps and .../.pdf).Comments, corrections, and related references are welcomed, as always!

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Cited by 8 publications
(10 citation statements)
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“…Taking complements, we have Σ 1 f −1 ab = Σ 1 , so as Σ 1 is full with respect to U , we can find c ∈ U {Σ1} which agrees on Σ 1 with the inverse of f −1 ab; that is, such that f −1 abc ∈ S (Σ1) . Now (2), applied to the inverse of the latter element, gives us…”
Section: Introduction Notation and Some Lemmas On Full Moietiesmentioning
confidence: 99%
“…Taking complements, we have Σ 1 f −1 ab = Σ 1 , so as Σ 1 is full with respect to U , we can find c ∈ U {Σ1} which agrees on Σ 1 with the inverse of f −1 ab; that is, such that f −1 abc ∈ S (Σ1) . Now (2), applied to the inverse of the latter element, gives us…”
Section: Introduction Notation and Some Lemmas On Full Moietiesmentioning
confidence: 99%
“…Clearly the first assertion is a case of the second. To prove the latter, let us, for any poset P, write fdown(P ) for the upper semilattice of finite nonempty unions of principal downsets of P. Then one can verify that (2) fdown(P ) ∼ = the upper semilattice freely generated by the poset P.…”
Section: Nonexistence Of Surjectionsmentioning
confidence: 99%
“…We will show that E = M i for some i ∈ I.By the preceding lemma, Ω contains a full moiety with respect to some M i . Thus, Lemma 2 implies that E = M i ∪ {g, h} for some g, h ∈ E. But, by the hypotheses onThis result is proved by a very different method in [3].…”
mentioning
confidence: 98%