1970
DOI: 10.1063/1.1665150
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Unique Hamiltonian Operators via Feynman Path Integrals

Abstract: The old problem of how to represent uniquely a prescribed classical Hamiltonian H as a well-defined quantal operator Ĥ is shown to have a clear answer within Feynman's path-integral scheme (as expanded by Garrod) for quantum mechanics. The computation of Ĥ involves the momentum Fourier transform of a coordinate average of H. A differential equation for a reduced form of the Feynman propagator giving Ĥ from H is found; and the example of polynomial H worked out to give the Born-Jordan ordering rule for Ĥ in thi… Show more

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Cited by 35 publications
(26 citation statements)
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“…By the way this is even used to define the prescription to evaluate the Feynmann path integral at the mean point [25][26] [27]. The way one chooses the point to evaluate the path integral is shown to be closely related to the problem of ordering ambiguity [28] [29]. In fact the so called Weyl ordering is usually accepted by some textbooks as the correct one [30][31].…”
Section: Introductionmentioning
confidence: 99%
“…By the way this is even used to define the prescription to evaluate the Feynmann path integral at the mean point [25][26] [27]. The way one chooses the point to evaluate the path integral is shown to be closely related to the problem of ordering ambiguity [28] [29]. In fact the so called Weyl ordering is usually accepted by some textbooks as the correct one [30][31].…”
Section: Introductionmentioning
confidence: 99%
“…We notice that the propagator K(x, x 0 , t, t 0 ) was postulated by Garrod [19], as well as Kerner and Sutcliffe [49], though they failed to prove the estimates (25) and (26). For details we refer to de Gosson's recent works [24,25].…”
Section: The Kerner and Sutcliffe Propagatormentioning
confidence: 99%
“…insertion of this value in (51) yields (49). We are now going to use equation (49) to derive formulas (47) and (48).…”
Section: Short-time Solutionsmentioning
confidence: 99%
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“…This criterion leads to a unique translation into a continuous functional integral. We can also take the perspective from the problem of operator ordering [14][15][16][17]. To think of the easiest example, the different operatorsxp andpx give the same zeroth order contribution in the action.…”
Section: Functional Integral In Quantum Mechanicsmentioning
confidence: 99%