“…Suppose N = 10, K = 3, the encoding dimension is (10 + 3 − 1) × 1 = 12 × 1, thus a possible encoding can be (0.12, 0.37, 0.22, 0.96, 0.56, 0.35, 0.76, 0.57, 0.38, 0.91, 0.71, 0.26). Using the random key decoding rule, it is easy to get the integer arrangement (1,5,2,12,7,4,10,8,6,11,9,3). The integers 11 and 12 are the so-called sub-path segmentation, and the vehicle routes are:…”