2015
DOI: 10.1007/s12555-014-0012-9
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Using AQM for performance improvement of networked control systems

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Cited by 15 publications
(17 citation statements)
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“…The linearization of the above model around an operating point ( w 0 , q 0 , p 0 ) yields {,centerδtruew˙(),t=Nτ02c0.2em(),italicδw(),t+italicδw(),tτ(),tcenter3.9em1τ02c0.2em(),italicδq(),t+italicδq(),tτ(),tcenter.5emτ02c2N20.2emitalicδp(),tτ(),tcenterδtrueq˙(),t=Nτ00.2emitalicδw(),t1τ00.2emitalicδq(),t in which δw = w − w 0 , δq = q − q 0 and operating point is w0=τ0N,p0=2w02 and τ0=q0C+Tp, which is obtained by setting truew˙(),t=0,trueq˙(),t=0. Therefore, the round trip delay τ ( t ) can be written as the sum of a fixed delay and a time varying delay, which depends on the queue length as below.…”
Section: Problem Statement and Preliminariesmentioning
confidence: 99%
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“…The linearization of the above model around an operating point ( w 0 , q 0 , p 0 ) yields {,centerδtruew˙(),t=Nτ02c0.2em(),italicδw(),t+italicδw(),tτ(),tcenter3.9em1τ02c0.2em(),italicδq(),t+italicδq(),tτ(),tcenter.5emτ02c2N20.2emitalicδp(),tτ(),tcenterδtrueq˙(),t=Nτ00.2emitalicδw(),t1τ00.2emitalicδq(),t in which δw = w − w 0 , δq = q − q 0 and operating point is w0=τ0N,p0=2w02 and τ0=q0C+Tp, which is obtained by setting truew˙(),t=0,trueq˙(),t=0. Therefore, the round trip delay τ ( t ) can be written as the sum of a fixed delay and a time varying delay, which depends on the queue length as below.…”
Section: Problem Statement and Preliminariesmentioning
confidence: 99%
“…Solid lines in Fig. denote the state responses with initial values 0.25emx0=centercenter1center1T using the control algorithm proposed in . By applying theorem 2 and using the LMI Toolbox of the MATLAB, the controller gains are obtained as follows: leftW=103*centercenter1.8257center0.2803center0center0center0.2803center0.2862center0center0center0center0center2.0836center0.0614center0center0center0.0614center0.0411Ktrue˜=centercenterY1center0center0centerY2W1=centercentercenter1.5858center0centercenter8.03center0centercenter0center0.0002centercenter0center0.0034Knormalp=centercenter1.5858center8.03,normalKnormaln=centercenter0.0002center0.0034 …”
Section: Numerical Simulationsmentioning
confidence: 99%
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