2011
DOI: 10.1016/j.jnnfm.2010.11.004
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Viscous dissipation of a power law fluid in axial flow between isothermal eccentric cylinders

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Cited by 17 publications
(8 citation statements)
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“…For this case, Eq . simplifies to, 0 = k { 1 h ξ 1 h T ξ + 1 h θ 1 h T θ } { τ ξ ζ 1 h v ζ ξ + τ θ ζ 1 h v ζ θ } The shear stress can be written in terms of the velocity gradients such that : τ ξ ζ = η 1 h v ζ ξ , τ θ ζ = η 1 h v ζ θ where, η is defined in Eq . ; v ζ , the velocity profile for the flow between the eccentric cylinders.…”
Section: Discussionmentioning
confidence: 99%
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“…For this case, Eq . simplifies to, 0 = k { 1 h ξ 1 h T ξ + 1 h θ 1 h T θ } { τ ξ ζ 1 h v ζ ξ + τ θ ζ 1 h v ζ θ } The shear stress can be written in terms of the velocity gradients such that : τ ξ ζ = η 1 h v ζ ξ , τ θ ζ = η 1 h v ζ θ where, η is defined in Eq . ; v ζ , the velocity profile for the flow between the eccentric cylinders.…”
Section: Discussionmentioning
confidence: 99%
“…For small dimensionless eccentricity, ε ≪ 1, the scale factor simplifies to as: h = a X = R 0 true( 1 ɛ cos β true) ( 1 ɛ 2 ) 1 2 where, X = 1 + ɛ cos θ ɛ = 1 ɛ 2 ɛ true( 1 ɛ cos β true) , and R 0 is the average radius, R 0 = R 1 + R 2 2 and β is measured from the x ‐axis as shown in Fig. .…”
Section: Methodsmentioning
confidence: 99%
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“…Feldman et al [9] have studied the problem of the thermal entrance region for the case of an incompressible Newtonian fluid; the dynamic regime is supposed fully developed and the temperature uniform at the entry, different thermal conditions being considered. When viscous dissipation is taken into account as it is encountered in polymers (non-Newtonian fluids) melting manufacturing, annular eccentric geometry is largely present, because the die mandrel is displaced downward to get a uniform annular shape at the exit as possible, this kind of problem have been studied numerically and analytically by several authors (see for instance [10,11]). For an eccentric curved annulus, Nobari et al [12] study numerically the problem for a Newtonian fluid using a second order finite difference method.…”
Section: Introductionmentioning
confidence: 99%