1983
DOI: 10.1016/0022-1236(83)90081-2
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Weakly continuous mappings on Banach spaces

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Cited by 147 publications
(98 citation statements)
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“…So we can our results in the case of operators that are defined on reflexive spaces. As a consequence of the main Theorem in [4] and Proposition 5.1, we obtain the following result (see also [1,3]). …”
Section: 1mentioning
confidence: 52%
“…So we can our results in the case of operators that are defined on reflexive spaces. As a consequence of the main Theorem in [4] and Proposition 5.1, we obtain the following result (see also [1,3]). …”
Section: 1mentioning
confidence: 52%
“…It follows from the Littlewood-Bogdanowicz-Pelczyriski Theorem (see [3,14]) that every n -homogeneous polynomial Q on c 0 is weakly continuous on bounded sets. Applying [2] we see that Q is also weakly uniformly continuous on bounded sets and in particular on B Co . It therefore follows from Goldstine's Theorem that there is a unique weak* continuous extension, Q, of Q to B too .…”
Section: >+mentioning
confidence: 89%
“…In the real case for every n > 1 the polynomial P(x) = x" -x"~2<f> 2 , where x = (xi,x 2 , ...),4> € CQ,0 < ||0|| < 1, is a norm-preserving extension of Q(x) = x " , x -(x t , x 2 ,...), to £oo which is different from x" on ^oo. In particular, x\ -<f> 2 is a norm-preserving extension of x\ to ^oo.…”
Section: Unique Norm-preserving Extensions From C 0 To Tâmentioning
confidence: 99%
See 1 more Smart Citation
“…admite base contrátil, e então pelo teorema 4.4.20 de [30] temos que l 1 → E, e assim, pela proposição 2.12 de [7] temos que P wu ( m E) = P wsc ( m E) para cada m ∈ IN. Então, se incondicional (x n ) n e F um espaço de Banach com uma base de Schauder (y n ) n equivalentè a base (x n ) n de E. Então existe um isomorfismo sobrejetor T : E −→ F tal que…”
Section: Para Quaisquer Duas Seqüênciasunclassified