2018
DOI: 10.1242/jeb.187369
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Wing inertia as a cause of aerodynamically uneconomical flight with high angles-of-attack in hovering insects

Abstract: Flying insects can maintain maneuverability in the air by flapping their wings, and, to save energy, the wings should operate following optimal kinematics. However, unlike conventional rotary wings, insects operate their wings at aerodynamically uneconomical and high angles of attack (AoA). Although insects have continuously received attention from biologists and aerodynamicists, the high AoA operation in insect flight has not been clearly explained. Here, we used a theoretical blade-element model to examine t… Show more

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Cited by 17 publications
(16 citation statements)
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“…The tailless robot is developed aiming to mimic the flight of horned beetle (Allomyrina dichotoma) known to be capable of hovering flight. 26 Since the mechanical design of the flapping-wing mechanism was presented in detail in ref., 17 this paper shows only a brief summary.…”
Section: Flapping-wing Mechanismmentioning
confidence: 99%
“…The tailless robot is developed aiming to mimic the flight of horned beetle (Allomyrina dichotoma) known to be capable of hovering flight. 26 Since the mechanical design of the flapping-wing mechanism was presented in detail in ref., 17 this paper shows only a brief summary.…”
Section: Flapping-wing Mechanismmentioning
confidence: 99%
“…Note that, in [3,4,5], the area density distribution was determined as the dissected wing segment mass divided by the respective area. Our approach of calculating separately the vein mass and the membrane mass is less straightforward, but it allows us to use only a small number of segments and still account for the important area density variation near the leading edges and the roots, because it is mainly due to the veins.…”
Section: F Estimation Of Moments Of Inertiamentioning
confidence: 99%
“…Calculation of the moments of inertia yields the following isometric scaling relationships: = 0.0014 5 , = 0.0426 5 , = −0.0010 5 , where R is in meters and the result is in kg ⋅ m 2 . For a wing of length = 15.2 mm , we obtain = 1.14 ⋅ 10 −12 kg ⋅ m 2 , = 34.6 ⋅ 10 −12 kg ⋅ m 2 , = −0.81 ⋅ 10 −12 kg ⋅ m 2 .…”
Section: B Wing Mass and Moments Of Inertiamentioning
confidence: 99%
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