Dedicated to Henk van der Vorst on the occasion of his 65th birthday.Abstract. The need to evaluate expressions of the form f (A)v, where A is a large sparse or structured symmetric matrix, v is a vector, and f is a nonlinear function, arises in many applications. The extended Krylov subspace method can be an attractive scheme for computing approximations of such expressions. This method projects the approximation problem onto an extended Krylov subspace K ℓ,m (A) = span{A −ℓ+1 v, . . . , A −1 v, v, Av, . . . , A m−1 v} of fairly small dimension, and then solves the small approximation problem so obtained. We review available results for the extended Krylov subspace method and relate them to properties of Laurent polynomials. The structure of the projected problem receives particular attention. We are concerned with the situations when m = ℓ and m = 2ℓ. . 1 e.g., by determining the spectral or Cholesky factorizations of T m . For instance, m steps of the Lanczos process applied to A with initial vector v yields the decompositionis symmetric and tridiagonal, g m ∈ R n , and V T m g m = 0. Here and below e j = [0, . . . , 0, 1, 0, . . . , 0] T denotes the jth axis vector and · the Euclidean vector norm. We tacitly assume that m is chosen small enough so that a decomposition of the form (1.3) exists. The columns of V m form an orthonormal basis for the Krylov subspaceThe expression (1.1) now can be approximated by(1.5) see, e.g., [4,10,14,21] for discussions on this approach. Indeed, if g m = 0, then w m = w. Moreover, let P m−1 denote the set of all polynomials of degree at most m − 1. Then f ∈ P m−1 implies that w m = w; see, e.g., [10] or [22, Proposition 6.3].The decomposition (1.3) and the fact that range(V m ) = K m (A, v) show that:i) The columns v j of V m satisfy a three-term recurrence relation. This follows from the fact that T m is tridiagonal. The vectors v j therefore are quite inexpensive to compute; only one matrix vector-product evaluation with A and a few vector operations are required to compute v j+1 from v j and v j−1 . ii) The columns v j can be expressed as