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Two reduction steps were observed in the electrochemical reduction of LiVO3 in molten normalLiCl‐normalKCl eutectic. The first reduction step produces an insoluble product which undergoes a chemical reaction with LiVO3 to form insoluble LiV2O5 and Li3VO4 . The second reduction step produces insoluble LiVO2 and Li3VO4 . LiVO2 undergoes a number of chemical reactions with LiVO3 to produce a mixture of solid compounds, one of which is LiV2O4 . VO2 was found to react with LiVO3 to produce LiV2O5 . The addition of oxide ion to the eutectic containing insoluble VO2 resulted in the disproportionation of VO2 to produce either Li3VO4 and V2O3 or Li3VO4 and LiVO2 , depending on the oxide concentration.

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Die elektrochemische LiVO3‐Reduktion in eutektischer LiCl‐KCl Schmelze bei 450°C erfolgt in einem Zweistufenprozeß.