2013
DOI: 10.2422/2036-2145.201103_005
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A Carleson-type estimate in Lipschitz type domains for non-negative solutions to Kolmogorov operators

Abstract: We prove a Carleson type estimate, in Lipschitz type domains, for non-negative solutions to a class of second order degenerate differential operators of Kolmogorov type of the formOur estimate is scale-invariant and generalizes previous results valid for second order uniformly parabolic equations to the class of operators considered.

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Cited by 5 publications
(5 citation statements)
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“…In the elliptic context we mention [33] for the Laplace operator in nontangentially accessible domains, [8], and [3], [4], [25] for elliptic operators in divergence and non-divergence form, respectively, [40], [41], for the p-Laplace operator, [12], [13] for the Kolmogorov operator.…”
Section: Introductionmentioning
confidence: 99%
See 1 more Smart Citation
“…In the elliptic context we mention [33] for the Laplace operator in nontangentially accessible domains, [8], and [3], [4], [25] for elliptic operators in divergence and non-divergence form, respectively, [40], [41], for the p-Laplace operator, [12], [13] for the Kolmogorov operator.…”
Section: Introductionmentioning
confidence: 99%
“…Indeed, in the critical and sub-critical range, explicit counterexamples rule out the possibility of a Harnack inequality. Only so-called Harnack-type estimates are possible, where, however, the ratio of infimum over supremum in proper space-time cylinders depends on the solution itself (for more details, see [21,Chapter 6,[11][12][13][14][15]).…”
Section: Introductionmentioning
confidence: 99%
“…In the homogeneous case, perhaps the most flexible proof of the Carleson estimate is due to [11] and has been adapted to many situations, see e.g., [1,3,4,14,17,18]. This proof relies on two basic estimates:…”
Section: Introductionmentioning
confidence: 99%
“…14), the definition of G and the condition G(1 2) = 0 to estimate(6.18)e e K+1 2−ε ≤ e R−(1+ε)s ds ≤ e e R−(1+ε) 4by possibly enlarging H min (ε). Therefore we may estimate the value of ψ at x by (6.18) and (6.15) and getψ(x) = G(3 8) − G(1 2) e R−(1+ε)s ds ≥ ce e R−7 16(1+ε) ≥ c e e R−(1+ε) 4 e −3 16−ε ≥ c e e K+1 2−ε e −3 16−ε (by (6.18)) = c e e K+1 4 e 1 16−2ε…”
mentioning
confidence: 99%
“…In these settings, more literature is available relating to the boundary behavior, in sufficiently regular domains, of nonnegative solutions to evolution equations (see e.g. the recent papers [6,7,13,27], and the references therein).…”
Section: Introductionmentioning
confidence: 99%