“…To this end, we need to find the amount of water that would have attenuation properties equivalent to each combination of water and bone traversed, so that FBHZD(tw, tb) = FBHZD(tw + (J(tw, tb), 0) = FBH1D(te) (2) where the line integral of the equivalent water path is given by te = tw + (J(tw, tb)' Following the ideas in [7,12,13], we approximate (J(tw, tb) to a second order polynomial only dependent on the amount of bone traversed by the X-rays:…”