1993
DOI: 10.1016/0026-2714(93)90070-f
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Cost benefit analysis of a complex system with correlated failures and repairs

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Cited by 3 publications
(9 citation statements)
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“…By taking the Laplace transform of equations ( 1)-(5) we can obtain A 0 * (s). Using this result, the steady state availability of the system is given by: where: 3) -p 67 (3) ) -p 64 (p 46 (5,2,3) + p 47 (5,2,3) )] 2) )p 64 + p 14 (2) p 60 ] + T 6 [p 14 (2) (p 46 (5,2,3) + p 47 (5,2,3) )…”
Section: Availability Analysismentioning
confidence: 99%
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“…By taking the Laplace transform of equations ( 1)-(5) we can obtain A 0 * (s). Using this result, the steady state availability of the system is given by: where: 3) -p 67 (3) ) -p 64 (p 46 (5,2,3) + p 47 (5,2,3) )] 2) )p 64 + p 14 (2) p 60 ] + T 6 [p 14 (2) (p 46 (5,2,3) + p 47 (5,2,3) )…”
Section: Availability Analysismentioning
confidence: 99%
“…By taking the Laplace transform of equations ( 7)-(11) we can get B 10 * (s) and the steady-state probability that the assistant repairman is busy is given by: where: 2) ) (1 -p 66 (3) -p 67 (3) ) -p 64 (p 46…”
Section: Availability Analysismentioning
confidence: 99%
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“…Suppose that the failed duplicate unit is non-repairable and replaced with an identical duplicate unit available instantaneously. Under this set-up, bivariate exponential distributions are the most commonly used models for the joint distribution of failure and repair/replacement times (see, for example, [13,17,25,14,26,18,15,16,[19][20][21][22][23][24]46]). If X and Y represent the failure time and the repair/replacement time, respectively, then the sum R = X + Y and the ratio W = X/(X + Y ) will be quantities of immediate interest.…”
Section: Introductionmentioning
confidence: 99%
“…Apart from being of interest in the statistical issues of reliability, these distributions have attracted many practical applications in reliability problems. Some recent references of applications from reliability journals are: [6,13,17,25,14,26,18,15,16,[19][20][21][22][23][24][44][45][46]. In these applications, one often encounters the problem of determining the sum and the ratio of the components of bivariate exponential distributions.…”
Section: Introductionmentioning
confidence: 99%