2017
DOI: 10.1142/s012905411750006x
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Deterministic Rendezvous with Detection Using Beeps

Abstract: Two mobile agents, starting at arbitrary, possibly different times from arbitrary nodes of an unknown network, have to meet at some node. Agents move in synchronous rounds: in each round an agent can either stay at the current node or move to one of its neighbors. Agents have different labels which are positive integers. Each agent knows its own label, but not the label of the other agent. In traditional formulations of the rendezvous problem, meeting is accomplished when the agents get to the same node in the… Show more

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Cited by 9 publications
(13 citation statements)
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“…On a more technical level, the beeping model differs from our circuit model in a sense that nodes are aware of their neighbors in the circuit model, which allows them to exchange (constant-sized) messages with each other, whereas in the beeping model, a listening node that receives a beep is not aware of the particular neighbor that beeped in that specific round. Several problems like interval coloring [5], maximal independent set [1,35], consensus [27], rendezvous of two agents [17], leader election [16,21] or clock synchronization [15,19,24,25] have already been investigated in the beeping model.…”
Section: Related Workmentioning
confidence: 99%
“…On a more technical level, the beeping model differs from our circuit model in a sense that nodes are aware of their neighbors in the circuit model, which allows them to exchange (constant-sized) messages with each other, whereas in the beeping model, a listening node that receives a beep is not aware of the particular neighbor that beeped in that specific round. Several problems like interval coloring [5], maximal independent set [1,35], consensus [27], rendezvous of two agents [17], leader election [16,21] or clock synchronization [15,19,24,25] have already been investigated in the beeping model.…”
Section: Related Workmentioning
confidence: 99%
“…On the other hand, the number of soft beeps heard by node u by round r must be at least 1/2 of the number of loud beeps it heard by round r. This implies 8 7 · 8 z ≥ 1 2 · 8 z+1 , which is a contradiction. This completes the first part of the proof.…”
Section: Part 2 Sendmentioning
confidence: 95%
“…In [19], various distributed problems were investigated under several variations of the beeping model from [6], and randomized emulations between these models were shown. In [8], the authors studied the task of rendezvous of agents communicating by beeps. The time of synchronous broadcasting and gossiping with beeps was studied in [7].…”
Section: Introductionmentioning
confidence: 99%
“…Their algorithm runs in O(log n) rounds, which matches the lower bound for that problem. Other problems that have been considered in this model are maximal independent set [AAB + 13, SJX13], leader election [FSW14,GN15] or rendevouz of two agents [EP17].…”
Section: Related Workmentioning
confidence: 99%