1992
DOI: 10.1002/net.3230220705
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Finding disjoint paths with different path‐costs: Complexity and algorithms

Abstract: Consider a network C = ( V , E ) with distinguished vertices s and t , and with k different costs on every edge. We consider the problem of finding k disjoint paths from s to t such that the total cost of the paths is minimized, where thejth edge-cost is associated with thejth path. The problem has several variants: The paths may be vertex-disjoint or arcdisjoint and the network may be directed or undirected. We show that all four versions of the problem are strongly NP-complete even for k = 2. We describe pol… Show more

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Cited by 72 publications
(51 citation statements)
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“…The objective of this problem is to find e disjoint paths such that the total length of the paths is minimized, where the f t h edge-length is associated with the f t h path. They showed that all four versions of the G-MIN-SUM e -path problem are strongly NP-complete even for e g h W [10]. In [12], we considered the problem of finding two disjoint paths such that the length of the shorter path is minimized (named the MIN-MIN 2-path problem).…”
mentioning
confidence: 99%
“…The objective of this problem is to find e disjoint paths such that the total length of the paths is minimized, where the f t h edge-length is associated with the f t h path. They showed that all four versions of the G-MIN-SUM e -path problem are strongly NP-complete even for e g h W [10]. In [12], we considered the problem of finding two disjoint paths such that the length of the shorter path is minimized (named the MIN-MIN 2-path problem).…”
mentioning
confidence: 99%
“…In [8], it was shown that in a network where the relationship between C a and C b on each link is arbitrary, the Min-Sum problem is NPC. A more restricted version of the problem was also studied, where for each and every link, C b ≤ C a .…”
Section: Computational Complexity Of Various Problemsmentioning
confidence: 99%
“…The Min-Sum problem in an arbitrary dual-cost network has been proved to be NPC [8]. But the network used in [8] for its NPC proof is not for MSOD (with ordered dual-cost links).…”
Section: Np-complete Proofmentioning
confidence: 99%
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