2017
DOI: 10.48550/arxiv.1708.08784
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Mean-field type Quadratic BSDEs

Abstract: In this paper, we give several new results on solvability of a quadratic BSDE whose generator depends also on the mean of both variables. First, we consider such a BSDE using John-Nirenberg's inequality for BMO martingales to estimate its contribution to the evolution of the first unknown variable. Then we consider the BSDE having an additive expected value of a quadratic generator in addition to the usual quadratic one. In this case, we use a deterministic shift transformation to the first unknown variable, w… Show more

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Cited by 4 publications
(6 citation statements)
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“…However, it gets much more complicated for the quadratic case, which needs further study (even for quadratic mean-field BSDEs, see, e.g. [13]).…”
Section: Lipschitz Casementioning
confidence: 99%
See 1 more Smart Citation
“…However, it gets much more complicated for the quadratic case, which needs further study (even for quadratic mean-field BSDEs, see, e.g. [13]).…”
Section: Lipschitz Casementioning
confidence: 99%
“…Applying Doob's maximal inequality and Hölder's inequality, we get that for each p ≥ 1 and t ∈ [0, T ], (13) and assumption (H4), we derive that…”
Section: Unbounded Terminal Conditionmentioning
confidence: 99%
“…The BSDE (3.6) is a quadratic one of conditional mean field type and it does not satisfy the assumptions in [14]. In particular, the quadratic growth in (3.6) comes from both ( Z, Z 0 ) and the conditional expectation of ( Z, Z 0 ).…”
Section: 3mentioning
confidence: 99%
“…We take à ≥ Ã0 and choose δ à as (24). For T ∈ (0, δ Ã], define (Y 0 , Z 0 , K 0 ) = (0, 0, 0) and by (8)…”
Section: Now We Definementioning
confidence: 99%
“…When the mean reflection constraint and resistance term vanish, it reduces to a standard mean field BSDE. For the study of mean-field BSDEs, we refer the reader to [6,8].…”
Section: Introductionmentioning
confidence: 99%