2013
DOI: 10.1137/120869808
|View full text |Cite
|
Sign up to set email alerts
|

Neumann--Dirichlet Nash Strategies for the Solution of Elliptic Cauchy Problems

Abstract: We consider the Cauchy problem for an elliptic operator, formulated as a Nash game. The overspecified Cauchy data are split between two players: the first player solves the elliptic equation with the Dirichlet part of the Cauchy data prescribed over the accessible boundary and a variable Neumann condition (which we call first player's strategy) prescribed over the inaccessible part of the boundary. The second player makes use correspondingly of the Neumann part of the Cauchy data, with a variable Dirichlet con… Show more

Help me understand this report

Search citation statements

Order By: Relevance

Paper Sections

Select...
2
2
1

Citation Types

0
32
0

Year Published

2015
2015
2023
2023

Publication Types

Select...
3
3

Relationship

0
6

Authors

Journals

citations
Cited by 21 publications
(32 citation statements)
references
References 27 publications
0
32
0
Order By: Relevance
“…Let be Ω a bounded open domain in R d (d = 2, 3) with a sufficiently smooth boundary ∂Ω composed of two connected disjoint components Γ c and Γ i , with the latter being inaccessible to boundary measurements. For details, see Habbal & Kallel (2013) whence the present example is excerpt.…”
Section: Problem Descriptionmentioning
confidence: 99%
See 2 more Smart Citations
“…Let be Ω a bounded open domain in R d (d = 2, 3) with a sufficiently smooth boundary ∂Ω composed of two connected disjoint components Γ c and Γ i , with the latter being inaccessible to boundary measurements. For details, see Habbal & Kallel (2013) whence the present example is excerpt.…”
Section: Problem Descriptionmentioning
confidence: 99%
“…Theorem 1 (Habbal & Kallel, 2013) There always exists a unique Nash equilibrium (η * , ζ * ) ∈ H − 1 2 (Γ i ) × H 1 2 (Γ i ), and when the Cauchy problem has a solution u, then u 1 (η * ) = u 2 (ζ * ) = u, and (η * , ζ * ) are the missing data, namely η * = λ∇u.ν |Γi and ζ * = u |Γi .…”
Section: Problem Descriptionmentioning
confidence: 99%
See 1 more Smart Citation
“…. On the other hand let (ϕ, ψ) ∈ Ker(P Γ2 − I Γ2 ) and let the function v defined by (15).Using again trace formulas for double and single layer potentials, we obtain…”
Section: Analysis Of Operators a And Bmentioning
confidence: 99%
“…Consequently (ϕ, ψ) ∈ Ker(T Γ2→Γ1 ). The proof of b) uses similar arguments as the proof of a) and is based on considering v defined by (15) where Γ 2 is replaced with Γ 1 , namely…”
Section: Analysis Of Operators a And Bmentioning
confidence: 99%