1998
DOI: 10.1007/bf02310299
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On a property ofL p spaces on semifinite von Neumann algebras

Abstract: ABSTRACT. A characterization of the traces in a broad class of weights on yon Neumann algebras is obtained. A new property of the "domain ideals ~ of these traces is proved. In the semifinite case, a relation for a faithful normal trace is established. This result is new even for the algebra of all bounded operators on a Hilbert space. Applications of the main result to the structure theory of yon Neumann algebras and to the K5the duality theory for ideal spares of Segal measurable operators are given.KEY woRD… Show more

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Cited by 29 publications
(14 citation statements)
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“…We assert that this implies that l is tracial, i.e.,l (X Y ) = l (Y X ), X , Y ∈ A . To verify this, we apply an idea from the proof of Lemma 1 in [4]. Namely, select an arbitrary pair P,Q of projections in A , define S = I − 2P and compute…”
Section: If and Only If L Is Tracialmentioning
confidence: 99%
“…We assert that this implies that l is tracial, i.e.,l (X Y ) = l (Y X ), X , Y ∈ A . To verify this, we apply an idea from the proof of Lemma 1 in [4]. Namely, select an arbitrary pair P,Q of projections in A , define S = I − 2P and compute…”
Section: If and Only If L Is Tracialmentioning
confidence: 99%
“…In [15] (also see [16]) the author obtained the affirmative answer and constructed an example of p, q ∈ B(H ) pr with pqp ∈ S 1 but pq / ∈ S 1 , and in [16] he showed that for all ideals J of B(H ) distinct from the ideals of finite-dimensional and compact operators (for separable H with dim H = ∞) there exist p, q ∈ B(H ) pr with pqp ∈ J but pq / ∈ J. Thus, the operators pq and pqp are not always similar, and a cyclic permutation of projections in products under a trace in the general case of dim H = ∞ is inadmissible (also see [4]).…”
Section: New Properties Of Products Of Projectionsmentioning
confidence: 96%
“…Note that |a|(1 + D 2 ) −s/2 ∈ L 1 (N , τ ) by the polar decomposition a = v|a|, which does not require |a| to be in A. For the definition of spectral dimension to have meaning, we require that τ (a(1 + D 2 ) −s/2 ) ≥ 0 for a ≥ 0, a fact that follows from [12,Theorem 3]. For a semifinite spectral triple (A, H, D) to be finitely summable with spectral dimension p, it is a necessary condition that A ⊂ B 1 (D, p) [ We see that to define δ k (T ), we require that T : H k → H k for H k = k l=0 Dom(D l ).…”
Section: Appendix a Summary Of Non-unital Index Theorymentioning
confidence: 99%