“…Note that |a|(1 + D 2 ) −s/2 ∈ L 1 (N , τ ) by the polar decomposition a = v|a|, which does not require |a| to be in A. For the definition of spectral dimension to have meaning, we require that τ (a(1 + D 2 ) −s/2 ) ≥ 0 for a ≥ 0, a fact that follows from [12,Theorem 3]. For a semifinite spectral triple (A, H, D) to be finitely summable with spectral dimension p, it is a necessary condition that A ⊂ B 1 (D, p) [ We see that to define δ k (T ), we require that T : H k → H k for H k = k l=0 Dom(D l ).…”