2002
DOI: 10.1006/jnth.2001.2697
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On the Existence of Absolutely Simple Abelian Varieties of a Given Dimension over an Arbitrary Field

Abstract: We prove that for every field k and every positive integer n there exists an absolutely simple n-dimensional abelian variety over k. We also prove an asymptotic result for finite fields: For every finite field k and positive integer n, we let S(k, n) denote the fraction of the isogeny classes of n-dimensional abelian varieties over k that consist of absolutely simple ordinary abelian varieties. Then for every n we have S(F q , n) Q 1 as q Q . over the prime powers. © 2002 Elsevier Science (USA)

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Cited by 44 publications
(41 citation statements)
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“…Since an ordinary abelian variety over F q is simple if and only if its Weil polynomial is irreducible, we can look for the existence of simple ordinary jacobian varieties of every dimension. However, Howe and Zhu in [3] proved that for any finite prime fields there exist absolutely simple ordinary abelian varieties of every dimension. But the question of whether there exist absolutely simple jacobians of every dimension over a given finite field is still open (whereas the answer is yes if the field is the algebraic closure of a finite field, if it has characteristic p but is not algebraic over F p or if it has characteristic zero), see [3].…”
Section: Conjecturementioning
confidence: 97%
“…Since an ordinary abelian variety over F q is simple if and only if its Weil polynomial is irreducible, we can look for the existence of simple ordinary jacobian varieties of every dimension. However, Howe and Zhu in [3] proved that for any finite prime fields there exist absolutely simple ordinary abelian varieties of every dimension. But the question of whether there exist absolutely simple jacobians of every dimension over a given finite field is still open (whereas the answer is yes if the field is the algebraic closure of a finite field, if it has characteristic p but is not algebraic over F p or if it has characteristic zero), see [3].…”
Section: Conjecturementioning
confidence: 97%
“…Proof. By [15,Proposition 3], in order to prove that A is absolutely simple it is sufficient to prove that: (a) there is no d > 1 such that the characteristic polynomial of the Frobenius is in Z[T d ], and (b) there is no d > 1 and no primitive d-th root of unity ζ such that Q(π d ) is a proper sub-field of Q(π) and Q(π) = Q(π d , ζ). If (b) does not hold and Q(π) = Q(π d , ζ), then the degree ϕ(d) of the extension Q(ζ)/Q must divide deg Q(π) = 2 dim A.…”
Section: Cubic Threefoldsmentioning
confidence: 99%
“…Heuristically, over large finite fields, randomly sampled abelian varieties are vanilla with overwhelming probability. Indeed, being vanilla is invariant in isogeny classes, and Howe and Zhu have shown in [14,Theorem 2] that the fraction of isogeny classes of g-dimensional abelian varieties over F q that are ordinary and absolutely simple tends to 1 as q → ∞. All absolutely simple ordinary abelian varieties are vanilla, except those whose endomorphism algebras contain roots of unity; but the number of such isogeny classes for fixed g is asymptotically negligible.…”
Section: Vanilla Abelian Varietiesmentioning
confidence: 99%