“…To achieve a rate pair (R 1 , R 2 ), an element of R P j1,j2 but not that of R P * j1,j2 , we use steps similar to those used in [12,Lemma 2]. Precisely, the receivers choose r(j 1 , j 2 ) or s(j 1 , j 2 ) as zero and successful decoding takes place if the rate pair (R 1 , R 2 ) ∈ R P j1,j2 for the original choice of r(j 1 , j 2 ) and s(j 1 , j 2 ) for each (j 1 , j 2 ).…”