“…Output: Processed List: lst. 1 Let l and r be the size of lst 1 and lst 2 respectively; 2 Length of maximum used path in the combined graph 3 max ← max{lst (1,0) · , lst (2,0) · }; 4 Min number of edges to induce max in G p for p ∈ {1, 2}, 5 s p ← min{lst (p,j) ·η : lst (p,j) · ≥ max } ; 6 Min number of edges in lst, s ← s 1 + s 2 ; 7 Max number of edges in lst, f ← lst (1,l) ·η + lst (2,r) ·η; 8 for i ← s to f do 9 Find the possible edge divisions for i, I = (j 1 , j 2 ) : lst (1,j1) ·η + lst (2,j2) ·η = i ; 10 Find the cost maximizing division; 11 (opt 1 , opt 2 ) = arg max (j1,j2)∈I min lst (1,j1) · , lst (2,j2) · ; 12 i ← min{lst (1,opt1) · , lst (2,opt2) · } ; 13 Create the new element α, (α·η, α· , α·p1, α·p2) ← i, i , lst (1,opt1) , lst (2,opt2) ; 14 Insert α in list lst;…”