1970
DOI: 10.1109/tac.1970.1099352
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Pole placement using dynamic compensators

Abstract: A technique for t.he identificat.ion of linear systems," IEEE Trans.

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Cited by 340 publications
(70 citation statements)
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“…Since this is the final step, pole retention is no longer needed. There are two remaining poles to be assigned, thus k (2) contains no extra degrees of freedom. Therefore, k (2) is determined from equation (15) as In the above example, the general compensator obtained through the partial pole shows that all poles are successfully moved to the desired locations.…”
Section: Partial Pole Assignment Packagementioning
confidence: 99%
See 1 more Smart Citation
“…Since this is the final step, pole retention is no longer needed. There are two remaining poles to be assigned, thus k (2) contains no extra degrees of freedom. Therefore, k (2) is determined from equation (15) as In the above example, the general compensator obtained through the partial pole shows that all poles are successfully moved to the desired locations.…”
Section: Partial Pole Assignment Packagementioning
confidence: 99%
“…Pearson [2,8,9] found the relationship between the minimum order of the outputfeedback compensator and the controllability and observability indices. In addition,…”
Section: Introductionmentioning
confidence: 99%
“…When K is algebraically closed, the pole placement problem may be solved for q ≥ n − 1 [8] and q ≤ (n − mp)/(m + p − 1) is necessary [44] and sufficient [65] for generic systems. Thus for q large enough there exist stabilizing dynamic compensators.…”
Section: Feedback Control and Schubert Calculus Given A Strictly Promentioning
confidence: 99%
“…[28,291) or a dynamical output feedback (see e.g. [30]) can stabllIze an unstable system; recently, Youla et. al.…”
Section: I!!5 Stabilizationmentioning
confidence: 99%