The reaction of ReBr4, Te and TeBr4 in SiBr4 as solvent in a sealed glass ampoule at 150 °C yields black crystals of Re2Te6Br10. As the X‐ray crystal structure determination shows [monoclinic, P21, Z = 2, a = 1127.5(1), b = 861.85(9), c = 1231.0(2)pm, β = 105.47(9)°], the structure consists of discrete dinuclear complexes. A Re–Re dumb‐bell with d(Re–Re) = 279.9 pm is coordinated by a μ‐Te2 group and two μ‐TeBr groups. Additionally, each Re atom is coordinated to two terminal bromine atoms and a TeBr2 ligand leading to the formula [Re2Br4(Te2)(TeBr)2(TeBr2)2]. Re2Te6Br10 is one of only a few compounds known in the ternary system Re/Te/Br.