1934
DOI: 10.1021/ja01321a012
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The Equilibrium between Carbon Monoxide, Hydrogen, Formaldehyde and Methanol.1 II. The Reaction CO + 2H2 ⇌ CH3OH

Abstract: and Vogelb state that they have obtained samples with a specific conductivity of 1.05 X 10 ~8 mhos. We have found that acid of specific conductivity of about 0.60 X 10-8 mhos may be prepared in quantity without undue difficulty. Recently acid with a specific conductivity as low as 0.40 X 10~8 mhos has been prepared in this Laboratory. Our work would indicate that the influence of small amounts of moisture, responsible for the slight variations in the specific conductivity of the solvent, is without appreciable… Show more

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Cited by 18 publications
(6 citation statements)
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“…The results in Figure illustrate that the methanol synthesis at higher H 2 /CO ratios comes quite near the equilibrium boundary ( f MeOH /( K f f H 2 2 f CO ) = 1). There is a significant scattering in the literature concerning the exact location of the methanol synthesis equilibrium, and it is possible to find equilibrium constants both above and below the value used in the present case. , There is thus some uncertainty regarding the exact degree of equilibration for the methanol synthesis, but in light of the results in Figure it does seem most likely that the beginning stagnation of the methanol synthesis rate at the highest H 2 /CO ratios in Figure can be ascribed to the growing importance of the reverse reaction of . As described in section , the fugacity coefficients have been determined by means of the SRK equation of state.…”
Section: Resultsmentioning
confidence: 75%
“…The results in Figure illustrate that the methanol synthesis at higher H 2 /CO ratios comes quite near the equilibrium boundary ( f MeOH /( K f f H 2 2 f CO ) = 1). There is a significant scattering in the literature concerning the exact location of the methanol synthesis equilibrium, and it is possible to find equilibrium constants both above and below the value used in the present case. , There is thus some uncertainty regarding the exact degree of equilibration for the methanol synthesis, but in light of the results in Figure it does seem most likely that the beginning stagnation of the methanol synthesis rate at the highest H 2 /CO ratios in Figure can be ascribed to the growing importance of the reverse reaction of . As described in section , the fugacity coefficients have been determined by means of the SRK equation of state.…”
Section: Resultsmentioning
confidence: 75%
“…In terms of entropy, the syngas formation seems to be preferable, since coupling reduces the number of molecules and each molecule in the gas phase has a high translation entropy. In contrast, the formation of H 2 CO is energetically favorable over the formation of syngas by 0.13 eV [17] . This difference is relatively small compared to the large difference between the different tantalum structural isomers.…”
Section: Resultsmentioning
confidence: 90%
“…This is probably due to the fact that the experimental determination of chemical equilibria is difficult because of the occurrence of simultaneous reactions, which convert CO to other products. As a consequence, above 10 MPa very little data are available and with a marked degree of scatter (von Wettberg and Dodge, 1930;Newton and Dodge, 1934;Graaf et al, 1986). Therefore, only simulations will be presented here.…”
Section: Resultsmentioning
confidence: 99%