2011
DOI: 10.1007/978-3-642-22212-2_17
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Tight Bounds for Scattered Black Hole Search in a Ring

Abstract: Abstract. We study the problem of locating a particularly dangerous node, the so-called black hole in a synchronous anonymous ring network with mobile agents. A black hole destroys all mobile agents visiting that node without leaving any trace. Unlike most previous research on the black hole search problem which employed a colocated team of agents, we consider the more challenging scenario when the agents are identical and initially scattered within the network. Moreover, we solve the problem with agents that … Show more

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Cited by 13 publications
(4 citation statements)
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“…It is interesting to compare our results with the situation in a synchronous, oriented, anonymous ring, which can be seen as a one dimensional torus ( [2]): The minimum trade-offs between the number of agents and the number of tokens, in this case, are 4 agents with 2 unmovable tokens or 3 agents with 1 movable token each. Additionally, in an unoriented ring the minimum trade-offs are 5 agents with 2 unmovable tokens or 3 agents with 1 movable token each whereas the situation in an unoriented torus has not been studied.…”
Section: Discussionmentioning
confidence: 99%
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“…It is interesting to compare our results with the situation in a synchronous, oriented, anonymous ring, which can be seen as a one dimensional torus ( [2]): The minimum trade-offs between the number of agents and the number of tokens, in this case, are 4 agents with 2 unmovable tokens or 3 agents with 1 movable token each. Additionally, in an unoriented ring the minimum trade-offs are 5 agents with 2 unmovable tokens or 3 agents with 1 movable token each whereas the situation in an unoriented torus has not been studied.…”
Section: Discussionmentioning
confidence: 99%
“…The main idea of the algorithm is to make two agents meet whenever they are close to each other (this requires a complicated synchronization and checking procedure). If any two agents manage to gather at a node, we can easily solve BHS using the standard procedure for colocated agents 2 with the time-out mechanism (see [2,4]) . On the other hand, if the agents are always far away from each other (i.e.…”
Section: Sketch Of the Algorithmmentioning
confidence: 99%
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